persamaan garis yang melalui titik 2,-3 dan tegak lurus x+2y-5 =0

X+2y-5 = 0

M1 = -a/b = -1/2
Karena tegak lurus maka,
M1 × m2 = -1
-1/2 × m2 = -1
M2 = 2

Melalui titik(2,-3)
Y-y1= m2(x-x1)
Y-(-3) = 2(x-2)
Y+3 = 2x-4
Y = 2x-4-3
Y = 2x-7