jika fungsi f(x)=x^2+(k+2)x+c memiliki titik balik {-3,14}, hitunglah k dan c tolong bantu pake Jalan fast!

titik balik (x,y) = (-3,14)
x = -b/2a = -(k+2)/1
-3 = -k - 2
-3 + 2 = -k
-1 = -k
k = 1
f(x) = x² + (1+2)x + c
f(x) = x² + 3x + c
f(-3) = 14
(-3)² + 3(-3) + c = 14
9 - 9 + c = 14
c = 14