jika fungsi f(x)=x^2+(k+2)x+c memiliki titik balik {-3,14}, hitunglah k dan c *Bantu dong pake jalan yah pls ttg fungsi

f (x) = x^2 +(k+2)x + C. Puncak (-3,14)
sumbu simetri x = -b/2a = -3
-(k+2)/2.1 = -3
(k+2)/2 = 3
k + 2 = 6
k = 6 - 2 = 4. maka
f (x) = x^2 + 6x + c . grafik melalui puncak (-3,14)
(-3)^2 + 6(-3) + c = 14
9 - 18 + c = 14
-9 + c = 14
c = 14 + 9 = 23
jadi k = 4 dan c = 23. semoga bermanfaat..!