Matematika

Pertanyaan

X^2+2x-3/6-3x-3x^2 ≤ 2

1 Jawaban

  • (x²+2x-3)/(6-3x-3x²) ≤ 2
    (x²+2x-3)/(6-3x-3x²) - 2 ≤ 0
    {(x²+2x-3)/(6-3x-3x²)} - {2(6-3x-3x²)/(6-3x-3x²) ≤0
    {(x²+2x-3)-2(6-3x-3x²)} / (6-3x-3x²) ≤ 0
    {x²+2x-3-12+6x+6x²} / (2+x)(3-3x) ≤ 0
    (7x²+8x-15) / (2+x)(3-3x) ≤ 0
    (7x+15)(x-1) / (2+x)(3-3x) ≤ 0
    - - - - - + + + + - - - - + + +
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    ````` -15/7 ```` -2 ``````` 1
    x ≤ -15/7 atau -2 < x < 1

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