tentukn bilok Cr3(PO4) 3 Mn(NO3) 3 BaCr2O7 Pb(SO4)2 Tolong jawab saya butuh

Cr3(PO4)3 ==> 3Cr^3+ + 3PO4^3-
Biloks
Cr : +3
PO4 = -3
B.o P + 4(-2) = -3
B.o PO = -3 + 8 = +5

Mn(NO3)3 => Mn^3+ + 3NO3^-
Biloks
Mn= +3
NO3 = -1
B.o N + 3(-2) = -1
B.o N = -1 +6 = +5

BaCr2O7 => Ba^2+ + Cr2O7^2-
Bioks
Ba=+2
Cr2O7 = -2
2 B. O Cr + 7(-2) = -2
2 B.o Cr =-2+14
B.o Cr = 12/2=+6

Pb(SO4)2=> Pb^2+ + 2SO4^2-
Biloks
Pb = +2
SO4 =-2
B.O S + 4(-2)= -2
B.o S = -2+8=+6