Matematika

Pertanyaan

tentukan himpunan penyelesaian persamaan berikut a. 9^2x-4=(1/27)^x^2-4

1 Jawaban

  • [tex] 9^{2x-4}=( \frac{1}{27} )^{ x^{2} -4} \\ \\ 3^{2(2x-4)} = 3^{-3( x^{2} -4)} \\ \\ 2(2x-4) = -3( x^{2} -4) \\ 4x-8 = -3 x^{2} +12 \\ 3 x^{2} +4x-8-12 = 0 \\ 3 x^{2} + 4x - 20 = 0 \\ (3x + 10)(x - 2) = 0 \\ \\ 3x + 10 = 0 \\ 3x = -10 \\ x = - \frac{10}{3} \\ \\ x-2 = 0 \\ x = 2 [/tex]

    HP = {-10/3, 2)

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