tabung panjang diameternya 21cmdan tinggi 24cm hitung luas permukaan

D=21 cm
t=24 cm
L=2(phi)r(r+t) = (phi)(D)(r+t)
→ L=(22/7)(21)(10,5+24)
→ L=66(34,5)
→ L=2277 cm^2

r = 21 : 2 = 10,5
LP = 2 × [tex] \pi [/tex]× r (r + t)
= 2 × 3,14 × 10,5 (10,5 + 24)
= 65,94 (34,5)
= 2.274,93
= 2.275

maaf kalau salah, semoga membantu