nilai dari ²log 7 + ½²log16 - ²log28=

[tex]
^2\log{7}+\frac{1}{2}\cdot^2\log{16}-^2\log{28}\\
=^2\log{\left(\frac{7\cdot16^{\frac{1}{2}}}{28}\right)}\\
=^2\log{\frac{4}{4}}\\
=^2\log{1}\\
=0
[/tex]