Matematika

Pertanyaan

Faktorkan.
(2x-10) akar 3 =
8x akar 3 - 64 =
64 log 8 =
8 log 512 akar 4 =

1 Jawaban

  • (2x-10) akar 3 = 2(x-5)√3
    8x akar 3 - 64 = 8(x√3-8)
    64 log 8 = 8²log8 =½ 8log8 = ½
    8 log 512 akar 4 = 2(8log8³) = 3.2(1)=6

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