jika diketahui log 2=0,3010 dan log 3 =0,4771, tentukan nilai logaritma berikut! A. log 25. B. log 90

Bab Logaritma
Matematika SMA Kelas X

A] log 25
= log (100/4)
= log 100 - log 4
= log 10² - log 2²
= 2 . log 10 - 2 . log 2
= 2 . 1 - 2 . 0,301
= 2 - 0,602
= 1,398

B] log 90
= log (10 x 9)
= log 10 + log 9
= 1 + log 3²
= 1 + 2 . log 3
= 1 + 2 . 0,4771
= 1 + 0,9542
= 1,9542