himpunan penyelesaian

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

^6log (x - 3) + ^6log (x + 7) - ^6log (3x - 1) = 0
^6log ((x - 3) . (x + 7) / (3x - 1)) = 0
(x - 3) (x + 7) / (3x - 1) = 6^0
x² + 4x - 21 = 1 . (3x - 1)
x² + 4x - 21 - 3x + 1 = 0
x² + x - 20 = 0
(x + 5) (x - 4) = 0
x + 5 = 0
x = -5

x - 4 = 0
x = 4

syarat
x - 3 > 0
x > 3

HP = { 4 }