apabila 7log 2=a dan2log3=b maka 6log 98 adalah

7log2 = a
2log3 = b
7log2×2log3 = 7log3 = ab

6log98

6log7×7×2

6log7 + 6log7 + 6log2

1 1 1
-------- + -------- + ---------
7log6 7log6 2log6

1 1
------------ + ----------- +
7log2×3 7log2×3
1
-----------
2log2×3

1
------------------ +
7log2+7log3
1
------------------ +
7log2+7log3
1
------------------
2log2+2log3

1 1 1
--------- + --------- + -------
a + ab a + ab 1 + b

2 1
--------- + -------
a + ab 1 + b

2(1 + b) + 1(a + ab)
------------------------
(a + ab) (1 + b)

2 + 2b + a + ab
-------------------------
a + b + ab + ab^2

7log 2 = a, 2log 3 = b
6log 98 = log 98 / log 6
= log (2.49) / log (2.3)
= ( log 2 + log 49 ) / ( log 2 + log 3 )
= ( log 2 + log 7^2 ) / ( log 2 + log 3 )
= ( log 2 + 2.log 7 )/ ( log 2 + log 3 ) ( beri bilangan pokok baru 2), sehingga
= ( 2log 2 + 2(2log 7) ) / ( 2log 2 + 2log 3 )
= ( 1 + 2/a ) / ( 1 + b )
= (a + 2) / a (b+ 1)
= ( a + 2 ) / ( ab + a )