integral 4(x-3) pangkat 2 di bagi x pangkat 5 dx

[tex]
\int{\frac{4(x-3)^2}{x^5}}dx=\int{\left(4(x^2-6x+9)x^{-5}\right)}dx=\int{\left(4x^{-3}-24x^{-4}+36x^{-5}\right)}dx=\frac{4}{-2}x^{-2}-\frac{24}{-3}x^{-3}+\frac{36}{-4}x^{-4}+C=-\frac{2}{x^2}+\frac{8}{x^3}-\frac{9}{x^4}+C[/tex]