Nilai 2 log 8 - 1/2 log 0,25 + 3 log 1/27 + 2 log 1
Matematika
yutiaggraini
Pertanyaan
Nilai 2 log 8 - 1/2 log 0,25 + 3 log 1/27 + 2 log 1
1 Jawaban
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1. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
^ = pangkat
²log 8 - ^(1/2)log 0,25 + ³log (1/27) + ²log 1
= ²log 2³ - ^(1/2)log (1/4) + ³log 3⁻³ + ²log 2⁰
= 3 . ²log 2 - ^(1/2)log (1/2)² - 3 . ³log 3 + 0 . ²log 2
= 3 - 2 - 3 + 0
= -2