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Pertanyaan

tentukan fraksi mol alkohol (C2H2OH) dalam larutan alkohol 75%

1 Jawaban

  • wt = 75 gram (Mr = 40)
    wp = 100 - 75 = 25 (Mr = 18)
    Xt = .........................................?

    nt = wt/Mr = 75/40 = 1,875 mol
    np = wp/Mr = 25/18 = 1,389 mol

    Xt = nt/(nt+np) = 1,875/(1,875+1,389) = 1,875/3,264 = 0,574

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