the mole fraction of solute and solvent if 15 gram of accetic acid (CH3COOH)is dissolved in 90 gram of water is

nt = massa terlarut/mr terlarut
nt = 15/60
nt = 0,25 mol

np = massa pelarut/mr pelarut
np = 90/18
np = 5 mol

fraksi mol pelarut
xp = np/nt+np
xp = 5/5+0,25
xp = 0,9524

fraksi mol terlarut
xt = 1-xp
xt = 1-0,9524
xt = 0,0476

solute 0.05 dan solvent 0.95