Jika x = 4 dan y = 5 serta z = x2M + 2xy + y2maka berapa xyz? tolong caranya....

[tex]z=x^2+2xy+y^2\\z=(x+y)^2\\z=(4+5)^2\\z=81\\\\xyz=4\times 5times 81\\=1620[/tex]

Dik: x = 4 , y =5 , z = x2M + 2xy + y2
Dit: xyz??
Jwb: x2M = 4*4 = 16 , 2xy = 2*4*5 = 40 , y2 = 5*5 = 25
Jadi z = x2M + 2xy + y2
= 16 + 40. + 25
= 81
Maka xyz = 4*5*81 = 1620