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1 Jawaban
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1. Jawaban refskyf
1/2H2 + 1/2Cl2 -> HCl ∆H=-21kkal
∆H = (1/2(H-H) + 1/2(Cl-Cl)) - (H-Cl)
-21 = 52 + 29 - H-Cl
H-Cl = 102 kkal