diketahui fungsi f(x)=ax+b.jika f(2)=-2 dan f(3)=13 ,tentukan nilai f(4)

f(2) = 2a + b f(3) = 3a + b
-2 = 2a + b 13 = 3a + b
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Eliminasi
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-2 = 2a + b
13 = 3a + b
---------------- -
-15= -a
a = 15
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Substitusi
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-2 =2.15 + b
-2 -30 = b
b = -32
Maka,
f(4) = 4a + b
f(4) = 4.15 +(-32)
f(4) = 60 - 32
f(4) = 28

Jadi, f(4) = 28

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