2006^2 - 2005^2 + 2004^2 - 2003^2 + ... + 2^2 - 1^2 =
Matematika
elalivi22
Pertanyaan
2006^2 - 2005^2 + 2004^2 - 2003^2 + ... + 2^2 - 1^2 =
1 Jawaban
-
1. Jawaban Anonyme
(2006² - 2005²) + (2004² - 2003²) + ... + (2² - 1²)
= (2006 - 2005)(2006 + 2005) + (2004 - 2003)(2004 + 2003) + (2 - 1) + (2 + 1)
= 2006 + 2005 + 2004 + 2003 + ... + 2 + 1
= (1 + 2006) + (2 + 2005) + .... + (1003 + 1004
= 2007 × 2006/2
= 2013021