Diketahui ^4log 5 = p. Nilai ^2log 125 adalah...

⁴log 5 = p
²^²log 5¹ = p
(1/2) . ²log 5 = p  || X 2
²log 5 = 2p
²log 125 = ²log 5³ =  3 (²log 5) = 3(2p)= 6p

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

²log 125 = ^(√4)log 5³
              = ^(4^(1/2))log 5³
              = (3 : (1/2)) . ⁴log 5
              = 3 x 2 . p
              = 6p