Tentukan Jumlah 10 suku pertama deret : ⅛+¼+½+1+...

Bab Barisan dan Deret
Matematika SMP Kelas VIII

Geometri

a = 1/8

r = U2 : U1
  = 1/4 : 1/8
  = 1/4 x 8/1
  = 2

n = 10

Sn = (a x (rⁿ - 1)) / (r - 1)

S10 = (1/8 x (2¹⁰ - 1)) / (2 - 1)
       = (1/8 x (512 - 1)) / 1
       = 1/8 x 511
       = 511/8
       = 63 7/8

a = 1/8
r = U2 : U1
= 1/4 : 1/8
= 1/4 x 8/1
= 2

n : 10
sn : (axr^n-1)) / (r-1)
s10: (1/8x(512-1)) / 1
: 1/8x511
: 511/8
= 63 7/8

*SmgMembntu :)