Matematika

Pertanyaan

Tolong dibantu yaa.
Tolong dibantu yaa.

2 Jawaban

  • Kurang lebihnya kaya gitu... Maaf hanya nmer 5
    Gambar lampiran jawaban Endar027
  • 4a)
    5^1/2 2^(-2/3) 10^(-1)
    ----------------------------------
    5^(-7/2) 2^(-11/3) 10^(-3)

    = 5^(1/2-(-7/2)) 2^(-2/3-(-11/3)) 10^(-1-(-3))
    = 5^(1/2+7/2) 2^(-2/3+11/3) (5 2)^(-1+3)
    = 5^(8/4) 2^(9/3) 5^2 2^2
    = 5^2 2^3 5^2 2^2
    = 5^4 2^5

    b)
    (1/4)^(1/4) . 2 2^(1/2) . 1/4 (4^(1/4)) . 4 (16^(1/6))
    = 2^(-2(1/4)) . 2^(3/2) . 2^(-2) 2^2(1/4) . 2^2 2^4(1/6)
    = 2^(-1/2) . 2^(3/2) . 2^(-2) 2^(1/2) . 2^2 2^(2/3)
    = 2^(2/2) . 2^(-3/2) . 2^(8/3)
    = 2^(13/6)

    c)
    V[a^(3/2-(-3/2)) b^(1/4-(-5/4))]
    = V[a^(3/2+3/2) b^(1/4+5/4)]
    = V[a^(6/2) b^(6/4)]
    = [a^3 b^(3/2)]^(1/2)
    = a^(3/2) b^(3/4)


    5)
    [8^(2x-1)]^(1/4) = 1/32
    [2^3(2x-1)]^(1/4) = 1/(2^5)
    2^((6x-3)/4) = 2^(-5)
    (6x - 3)/4 = -5
    6x - 3 = -5 × 4
    6x - 3 = -20
    6x = -20 + 3
    6x = -17
    x = -17/6