Tolong dibantu yaa.
Matematika
Afifahanggra
Pertanyaan
Tolong dibantu yaa.
2 Jawaban
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1. Jawaban Endar027
Kurang lebihnya kaya gitu... Maaf hanya nmer 52. Jawaban Sutr1sn0
4a)
5^1/2 2^(-2/3) 10^(-1)
----------------------------------
5^(-7/2) 2^(-11/3) 10^(-3)
= 5^(1/2-(-7/2)) 2^(-2/3-(-11/3)) 10^(-1-(-3))
= 5^(1/2+7/2) 2^(-2/3+11/3) (5 2)^(-1+3)
= 5^(8/4) 2^(9/3) 5^2 2^2
= 5^2 2^3 5^2 2^2
= 5^4 2^5
b)
(1/4)^(1/4) . 2 2^(1/2) . 1/4 (4^(1/4)) . 4 (16^(1/6))
= 2^(-2(1/4)) . 2^(3/2) . 2^(-2) 2^2(1/4) . 2^2 2^4(1/6)
= 2^(-1/2) . 2^(3/2) . 2^(-2) 2^(1/2) . 2^2 2^(2/3)
= 2^(2/2) . 2^(-3/2) . 2^(8/3)
= 2^(13/6)
c)
V[a^(3/2-(-3/2)) b^(1/4-(-5/4))]
= V[a^(3/2+3/2) b^(1/4+5/4)]
= V[a^(6/2) b^(6/4)]
= [a^3 b^(3/2)]^(1/2)
= a^(3/2) b^(3/4)
5)
[8^(2x-1)]^(1/4) = 1/32
[2^3(2x-1)]^(1/4) = 1/(2^5)
2^((6x-3)/4) = 2^(-5)
(6x - 3)/4 = -5
6x - 3 = -5 × 4
6x - 3 = -20
6x = -20 + 3
6x = -17
x = -17/6Pertanyaan Lainnya