Matematika

Pertanyaan

nomer 1 - 3
ada jalan ceritanya * rumusnya *
nomer 1 - 3 ada jalan ceritanya * rumusnya *

1 Jawaban

  • 1.a
    dik : d = 6cm > r = 3cm
    t = 20cm

    v = phi×r^×t
    v = 3,14×3×3×20
    v = 565,2cm3
    1.b
    dik : d = 14cm > r = 7cm
    t = 36cm


    v = phi×r^×t
    v = 22/7×7×7×36
    v = 5.544cm3
    1/2 v = 5.544 ÷ 2
    = 2.772cm3


    2. dik : v = 6.930cm3
    r = 21cm
    phi = 22/7

    v = phi×r^×t
    6.930 = 22/7×21×21×t (21÷7=3) > (22×3×21)
    6.930 = 9.702/7×t
    6.930 = 1386×t
    6930÷1386 = t
    5 = t > t = 5cm

    3. dik : v = 352cm3
    t = 7cm
    phi = 22/7

    v = phi×r^×t
    352 = 22/7×r^×7 (7÷7 = 1)
    352 = 22×r^
    352÷22 = 16
    r^ = 16 ( r = akar 16 )
    r = 4cm


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