nomer 1 - 3 ada jalan ceritanya * rumusnya *
Matematika
ameliariskki
Pertanyaan
nomer 1 - 3
ada jalan ceritanya * rumusnya *
ada jalan ceritanya * rumusnya *
1 Jawaban
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1. Jawaban seadanya
1.a
dik : d = 6cm > r = 3cm
t = 20cm
v = phi×r^×t
v = 3,14×3×3×20
v = 565,2cm3
1.b
dik : d = 14cm > r = 7cm
t = 36cm
v = phi×r^×t
v = 22/7×7×7×36
v = 5.544cm3
1/2 v = 5.544 ÷ 2
= 2.772cm3
2. dik : v = 6.930cm3
r = 21cm
phi = 22/7
v = phi×r^×t
6.930 = 22/7×21×21×t (21÷7=3) > (22×3×21)
6.930 = 9.702/7×t
6.930 = 1386×t
6930÷1386 = t
5 = t > t = 5cm
3. dik : v = 352cm3
t = 7cm
phi = 22/7
v = phi×r^×t
352 = 22/7×r^×7 (7÷7 = 1)
352 = 22×r^
352÷22 = 16
r^ = 16 ( r = akar 16 )
r = 4cm
maaf kalo salah