Tentukan nilai × dan y dari sistem persamaan 3× +2y=12 4× - 3y =50

3x+2y=12
3x=12-2y
x=4-2/3y
x=4-2/3y, y(0,6)

4x-3y=50
4x=50+3y
x=25/2+3/4y
x=25/2+3/4y, y (0,-50/3)

3× +2y=12 x4
4× - 3y =50 x3
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12x + 8y = 48
12x - 9y = 150
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17y = -102
y = -102/17
y = 6

3x + 2y = 12
3x + 2(6) = 12
3x + 12 = 12
3x = 0
x = 0/3
x = 0