bantu jawab ya.........

S^2 = r^2 + t^2
= 12^2 + 16^2
= 144 + 256
= 400
S = √400
= 20
Luas sisi kerucut = πr(r+s)
= 3,14 x 12 (12+20)
= 37,68 x 32
= 1205,76

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